Title: Engineering Economics Analysis for Engineering Projects Cost Analysis
Version: 1.0.0
Maintainer: Liya Abera <liya.eshetu.abera@gmail.com>
Description: Computing economic analysis in civil infrastructure and ecosystem restoration projects is a typical activity. This package contains Standard cost engineering and engineering economics methods that are applied to convert between present, future, and annualized costs. Newnan D. (2020) <ISBN 9780190931919> “Engineering Economic Analysis”.
License: GPL-3
URL: GitHub (<https://github.com/USACE-WRISES>)
Encoding: UTF-8
RoxygenNote: 7.3.1
Depends: R (≥ 4.1.0)
NeedsCompilation: no
Packaged: 2024-04-02 22:07:22 UTC; SHARIFUL ISLAM
Author: Liya Abera ORCID iD [aut, cre], S. Kyle McKay ORCID iD [aut]
Repository: CRAN
Date/Publication: 2024-04-03 19:53:00 UTC

Calculate future value from a uniform annual payment annual_to_future Compute future values from uniform annual payments using uniform series compound amount factor (uscaf)

Description

Calculate future value from a uniform annual payment

annual_to_future Compute future values from uniform annual payments using uniform series compound amount factor (uscaf)

Usage

annual_to_future(i, n, A)

Arguments

i

discount rate in percent per year

n

life span in years

A

series of uniform annual payments

Value

FV

References

Newnan, D. G., Eschenbach, T. G., Lavelle, J. P., & Oxford, N. Y. Engineering Economic Analysis, 14th ed. New York, Oxford University Press, 2020

David, W., & Terry, R. Fundamentals of Engineering Economics and Decision Analysis. Springer Nature, 2012

Examples

 
# Result: FV = 5664161
annual_to_future(0.08, 30, 50000)

Calculate present value from a uniform annual payment annual_to_present Compute present value from uniform annual payments using uniform series present worth factor (uswf)

Description

Calculate present value from a uniform annual payment

annual_to_present Compute present value from uniform annual payments using uniform series present worth factor (uswf)

Usage

annual_to_present(i, n, A)

Arguments

i

discount rate in percent per year

n

life span in years

A

series of uniform annual payments

Value

pr.value

References

Newnan, D. G., Eschenbach, T. G., Lavelle, J. P., & Oxford, N. Y. Engineering Economic Analysis, 14th ed. New York, Oxford University Press, 2020

David, W., & Terry, R. Fundamentals of Engineering Economics and Decision Analysis. Springer Nature, 2012

Examples

 
# Result: pr.value = $337733.5
annual_to_present(0.08, 30, 30000)

Calculate present value and annual value from a given future payments of cash flows cashflow Compute a given cash flow data's present value and annual value. The first column is the cash flow year;the rest is the cash flow money. The number of rows is the lifespan

Description

Calculate present value and annual value from a given future payments of cash flows

cashflow Compute a given cash flow data's present value and annual value. The first column is the cash flow year;the rest is the cash flow money. The number of rows is the lifespan

Usage

cashflow(i, cashflowdata)

Arguments

i

annual interest rate in percentage

cashflowdata

cash flow data containing the life span and money value of the cash flow for each year

Value

cash.flow.table

Examples

# Result : cash.flow.table  
# Result : future value = 232540.78
# Result : present value = 206330.96   
year = c(1:5)             
capital = c(63000,1300,1300,1600,1300)
year1 = c(60000,0,10000,0,0)
year2 = c(0,0,30000,50000,0)
cashflowdata <- data.frame (year, capital, year1, year2)
cashflow(0.055, cashflowdata)

Calculate effective annual interest rate for a known nominal rate and compounding period per year effective_i Compute future value nominal rate and compounding period per year, and frequency.

Description

Calculate effective annual interest rate for a known nominal rate and compounding period per year

effective_i Compute future value nominal rate and compounding period per year, and frequency.

Usage

effective_i(r, m = c("yearly", "quarterly", "monthly"))

Arguments

r

nominal interest rate in decimal number

m

number of compounding period per year monthly = 12 Quarterly = 4 yearly = 1

Value

effective_i

References

Newnan, D. G., Eschenbach, T. G., Lavelle, J. P., & Oxford, N. Y. (2020). Engineering Economic Analysis (14th ed.). New York, Oxford University Press.

David, W., & Terry, R. (2012). Fundamentals of Engineering Economics and Decision Analysis. Springer Nature.

Examples

 
# Result: effective_i = 
effective_i (0.08, m = "yearly")

Compute annual payment value from future value future_to_annual calculate annual value from future value using the accumulated amount after years using sinking fund factor (sff)

Description

Compute annual payment value from future value

future_to_annual calculate annual value from future value using the accumulated amount after years using sinking fund factor (sff)

Usage

future_to_annual(i, n, FV)

Arguments

i

discount rate in percent per year

n

life span in years

FV

accumulated (future) value

Value

A

References

Newnan, D. G., Eschenbach, T. G., Lavelle, J. P., & Oxford, N. Y. Engineering Economic Analysis, 14th ed. New York, Oxford University Press, 2020

David, W., & Terry, R. Fundamentals of Engineering Economics and Decision Analysis. Springer Nature, 2012

Examples

 
# Result: A = 5737.83
future_to_annual(0.08, 30, 650000)

Compute present values from future payments (or cash flow) future_to_present calculate present value from future value using present worth factor (pwf)

Description

Compute present values from future payments (or cash flow)

future_to_present calculate present value from future value using present worth factor (pwf)

Usage

future_to_present(i, n, FV)

Arguments

i

discount rate in percent per year

n

life span in years

FV

future value

Value

pr.value

References

Newnan, D. G., Eschenbach, T. G., Lavelle, J. P., & Oxford, N. Y. Engineering Economic Analysis, 14th ed. New York, Oxford University Press, 2020

David, W., & Terry, R. Fundamentals of Engineering Economics and Decision Analysis. Springer Nature, 2012

Examples

 
# Result: pr.value = 2981.32
future_to_present(0.08, 30, 30000)

Calculate annual value from uniform gradient payment gradient_to_annual Compute annual value from uniform gradient payments using uniform gra present worth factor (ugaw)

Description

Calculate annual value from uniform gradient payment

gradient_to_annual Compute annual value from uniform gradient payments using uniform gra present worth factor (ugaw)

Usage

gradient_to_annual(i, n, G, A)

Arguments

i

discount rate in percent per year

n

life span in years

G

uniform gradient payments

A

initial annual payment

Value

ann.value

References

Newnan, D. G., Eschenbach, T. G., Lavelle, J. P., & Oxford, N. Y. Engineering Economic Analysis, 14th ed. New York, Oxford University Press, 2020

David, W., & Terry, R. Fundamentals of Engineering Economics and Decision Analysis. Springer Nature, 2012

Examples

 
# Result: ann.value = $ 105138.30
gradient_to_annual(0.08, 30, 6000, 50000)

Calculate future value from uniform gradient payment gradient_to_future Compute future value from uniform gradient payments using uniform gradient present worth factor (ugfw)

Description

Calculate future value from uniform gradient payment

gradient_to_future Compute future value from uniform gradient payments using uniform gradient present worth factor (ugfw)

Usage

gradient_to_future(i, n, G)

Arguments

i

discount rate in percent per year

n

life span in years

G

uniform gradient payments

Value

fr.value

References

Newnan, D. G., Eschenbach, T. G., Lavelle, J. P., & Oxford, N. Y. Engineering Economic Analysis, 14th ed. New York, Oxford University Press, 2020

David, W., & Terry, R. Fundamentals of Engineering Economics and Decision Analysis. Springer Nature, 2012

Examples

 
# Result: fr.value = $ 312312
gradient_to_future(0.08, 30,300)

Calculate present value from uniform gradient payment gradient_to_present Compute present value from uniform gradient payments using uniform gradient present worth factor (ugpw)

Description

Calculate present value from uniform gradient payment

gradient_to_present Compute present value from uniform gradient payments using uniform gradient present worth factor (ugpw)

Usage

gradient_to_present(i, n, G)

Arguments

i

discount rate in percent per year

n

life span in years

G

uniform gradient payments

Value

pr.value

References

#' Newnan, D. G., Eschenbach, T. G., Lavelle, J. P., & Oxford, N. Y. Engineering Economic Analysis, 14th ed. New York, Oxford University Press, 2020

David, W., & Terry, R. Fundamentals of Engineering Economics and Decision Analysis. Springer Nature, 2012

Examples

 
# Result: pr.value = 310367.40
gradient_to_present(0.08, 30, 3000)

Compute interest during construction interest_during_construction calculate interest during construction using a monthly discount factor

Description

Compute interest during construction

interest_during_construction calculate interest during construction using a monthly discount factor

Usage

interest_during_construction(i, duration, capital)

Arguments

i

interest rate in percent per year

duration

construction duration in months

capital

first/capital cost

Value

idc

References

Engineer, U. S. A., & Resources, W. National Economic Development (NED) Procedures Manual- National Development Costs. U.S. Army Corps of Engineers Humphreys Engineer Center Support Activity Institute for Water Resources, DACWC72-90(June)1993.

Examples

 
# Result: idc ($) = 18992.14
interest_during_construction (0.027, 25, 700000)

Calculate the present value of periodic operations and maintenance costs om_distribute Distribute periodic present value operations and maintenance costs over a project life span, discount over project, and compute present value

Description

Calculate the present value of periodic operations and maintenance costs

om_distribute Distribute periodic present value operations and maintenance costs over a project life span, discount over project, and compute present value

Usage

om_distribute(i, n, fq, OM)

Arguments

i

discount rate in percent per year

n

life span in years

fq

frequency of cost in years

OM

operation and maintenance cost incurred at each interval in present value

Value

OM_dist

References

Add citation as needed.

Examples


#Result is the present value cost of periodic operations and maintenance expenses.
# Result: idc ($) = 8174.547
om_distribute(0.03, 50, 3, 1000)

Compute annual payment from present value present_to_annual Compute uniform series annual payments from present value using capital recovery factor (crf)

Description

Compute annual payment from present value

present_to_annual Compute uniform series annual payments from present value using capital recovery factor (crf)

Usage

present_to_annual(i, n, PV)

Arguments

i

discount rate in percent per year

n

life span in years

PV

present value

Value

ann.value

References

Newnan, D. G., Eschenbach, T. G., Lavelle, J. P., & Oxford, N. Y. Engineering Economic Analysis, 14th ed. New York, Oxford University Press, 2020

David, W., & Terry, R. Fundamentals of Engineering Economics and Decision Analysis. Springer Nature, 2012

Examples

# Result: ann.value = $17765.49
present_to_annual(0.08, 30, 200000)

Compute future values from present value

Description

present_to_future calculate future value from present value using compound amount factor (caf)

Usage

present_to_future(i, n, PV)

Arguments

i

discount rate in percent per year

n

life span in years

PV

present value

Value

fr.value

References

Newnan, D. G., Eschenbach, T. G., Lavelle, J. P., & Oxford, N. Y. Engineering Economic Analysis, 14th ed. New York, Oxford University Press, 2020

David, W., & Terry, R. Fundamentals of Engineering Economics and Decision Analysis. Springer Nature, 2012

Examples

 
# Result: fr.value = 9056391

present_to_future (0.08, 30, 900000)